r^2+2r=-11r+144

Solution for r^2+2r=-11r+144 equation:

r^2+2r=-11r+144

We move all terms to the left:

r^2+2r-(-11r+144)=0

We get rid of parentheses

r^2+2r+11r-144=0

We add all the numbers together, and all the variables

r^2+13r-144=0

a = 1; b = 13; c = -144;
Δ = b2-4ac
Δ = 132-4·1·(-144)
Δ = 745
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{745}}{2*1}=\frac{-13-\sqrt{745}}{2}
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{745}}{2*1}=\frac{-13+\sqrt{745}}{2}
$